Let
(S, f) be a game with
n players, where
Si is the strategy set for player
i,
S=S1 X S2 ... X Sn is the set of strategy profiles and
f=(f1(x), ..., fn(x)) is the payoff function for
x S. Let
xibe a strategy profile of player
i and
x-i be a strategy profile of all players except for player
i. When each player
i {1, ..., n} chooses strategy
xi resulting in strategy profile
x = (x1, ..., xn)then player
i obtains payoff
fi(x). Note that the payoff depends on the strategy profile chosen, i.e., on the strategy chosen by player
i as well as the strategies chosen by all the other players. A strategy profile
x* S is a Nash equilibrium (NE) if no unilateral deviation in strategy by any single player is profitable for that player, that is
A game can have either a pure-strategy or a mixed Nash Equilibrium, (in the latter a pure strategy is chosen stochastically with a fixed frequency). Nash proved that if we allow mixed strategies, then every game with a finite number of players in which each player can choose from finitely many pure strategies has at least one Nash equilibrium.
When the inequality above holds strictly (with > instead of ) for all players and all feasible alternative strategies, then the equilibrium is classified as a strict Nash equilibrium. If instead, for some player, there is exact equality between and some other strategy in the set S, then the equilibrium is classified as a weak Nash equilibrium.
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